Equivariant surgery with middle dimensional singular sets. II: Equivariant framed cobordism invariance

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5 Citations (Scopus)

Abstract

Let G be a finite group and let f : X → Y be a degree 1, G-framed map such that X and Y are simply connected, closed, oriented, smooth manifolds of dimension n = 2k ≧ 6 and such that the dimension of the singular set of the G-space X is at most k. In the previous article, assuming f is k-connected, we defined the G-equivariant surgery obstruction σ(f) in a certain abelian group. There it was shown that if σ(f) = 0 then f is G-framed cobordant to a homotopy equivalence f′ : X′ → Y. In the present article, we prove that the obstruction σ(f) is a G-framed cobordism invariant. Consequently, the G-surgery obstruction σ(f) is uniquely associated to f : X σ Y above even if it is not k-connected.

Original languageEnglish
Pages (from-to)2427-2440
Number of pages14
JournalTransactions of the American Mathematical Society
Volume353
Issue number6
Publication statusPublished - 2001

Fingerprint

Cobordism
Singular Set
Invariance
Obstruction
Equivariant
Surgery
Homotopy Equivalence
G-space
Smooth Manifold
Abelian group
Finite Group
Closed
Invariant

Keywords

  • Cobordism invariant
  • Equivariant surgery
  • Quadratic module
  • Surgery obstruction

ASJC Scopus subject areas

  • Mathematics(all)

Cite this

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AB - Let G be a finite group and let f : X → Y be a degree 1, G-framed map such that X and Y are simply connected, closed, oriented, smooth manifolds of dimension n = 2k ≧ 6 and such that the dimension of the singular set of the G-space X is at most k. In the previous article, assuming f is k-connected, we defined the G-equivariant surgery obstruction σ(f) in a certain abelian group. There it was shown that if σ(f) = 0 then f is G-framed cobordant to a homotopy equivalence f′ : X′ → Y. In the present article, we prove that the obstruction σ(f) is a G-framed cobordism invariant. Consequently, the G-surgery obstruction σ(f) is uniquely associated to f : X σ Y above even if it is not k-connected.

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